The area of an isosceles triangle is 12 m square. if one of its equal side is 5 M. Find it base.
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√s(s-a)(s-b)(s-c)=12
s=(a+b+c)/2
s=(a+5+5)/2
s=10+ a/2
√(10+a)/2(10+a/2+a)(10+a/2+5)(10+a/2+5)
=12
(10+a/2)(10+3a/2)(20+a/2)^2=12^2
(10+a/2)(10+3a/2)=144/100+10a+a²/4
25+5a+15a+3a²=144/(a/2+10)²
√(3a²/4+20a+25)=12/a/2+10
s=(a+b+c)/2
s=(a+5+5)/2
s=10+ a/2
√(10+a)/2(10+a/2+a)(10+a/2+5)(10+a/2+5)
=12
(10+a/2)(10+3a/2)(20+a/2)^2=12^2
(10+a/2)(10+3a/2)=144/100+10a+a²/4
25+5a+15a+3a²=144/(a/2+10)²
√(3a²/4+20a+25)=12/a/2+10
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