the area of an isosceles triangle is 300 CM square the height of the triangle is 15 cm find the perimeter of the triangle
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1/2bh is the area of ∆
so, 1/2×15×b = 300.
b = 300/15×2
b= 40
using Pythagoras theorem,
15^2+20^2=h^2
=25.
so, the hypotenuse is the other side.
we know that two sides of an isosceles ∆is equal.
so, the other side is also 25.
so, the perimeter is 25+25+40.
=90cm
so, 1/2×15×b = 300.
b = 300/15×2
b= 40
using Pythagoras theorem,
15^2+20^2=h^2
=25.
so, the hypotenuse is the other side.
we know that two sides of an isosceles ∆is equal.
so, the other side is also 25.
so, the perimeter is 25+25+40.
=90cm
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