Question

the area of an isosceles triangle is 8√ 18 cm square if base is 8 centimetres find the length of each of its equal sides ​

Answer 1

Answer:

the length of equal sides be X and X

base of triangle is 8 cm

area of triangle is 8√18cm^2

also area of triangle is

$\frac{1}{4} b \sqrt{4 {a}^{2} } - {b}^{2}$

$= \frac{1}{4} (8) \sqrt{4 {(2x)}^{2} } - {(8)}^{2} = 8 \sqrt{18} \\ = 2 \sqrt{4} (4 {x}^{2} ) - 64 = 8 \sqrt{18 } \\ = 2 \sqrt{16 {x}^{2} } - 64 = 8 \sqrt{18}$

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