Question

the area of an rectangular table top is5 3/8m² .if one of the side measures 2 1/4 m , find the length of other side.​

Answer 1

Answer:

Area =528m

Area =528m 2

Area =528m 2

Area =528m 2 Let Breadth be b

Area =528m 2 Let Breadth be bThen length l=2b+1

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0⇒2b

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0⇒2b 2

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0⇒2b 2 −32b+33b−528=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0⇒(2b+33)(b−16)=0

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0⇒(2b+33)(b−16)=0So b=16

Area =528m 2 Let Breadth be bThen length l=2b+1So (b)(2b+1)=528⇒2b 2 +b−528=0⇒2b 2 −32b+33b−528=0⇒2b(b−16)+33(b−16)=0⇒(2b+33)(b−16)=0So b=16l=33.

Step-by-step explanation:

YOU CAN SEE AN ATTACHMENT THAT I POST

Answer 2

Answer:

2 7/18 m

Step-by-step explanation:

5 3/8= 43/8

2 1/4= 9/4

Area = L x B

L of other side = (43/8)/(9/4)

43x4/9x8 = 43/18

= 2 7/18 m