Math, asked by kushal2341, 1 year ago

the area of base of a cylindrical vessel is 300 cm^2 water (density =1000 kg m^-3 )is poured into it up to a depth of 6 cm.calculate :(a) the pressure and (b) the thrust of water on the base.(g =10 m s^-2).

Answers

Answered by krutika2
3
Pressure=hpg=6×10*-2×1000×10
Force=pressure×area
Force=6×10*-2×1000×10×area
Force=6×10*-2×1000×10×300cm2
Force=6×10*-2×1000×10×300×10*-4m2
Force=18N
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