The area of circle inscribed in an equilateral triangle is 154 sq cm. What is the perimeter of the triangle?
(A) 21 cm (B)42√3 cm (C)21√3 cm(D)42 cm
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Answer:
Let r be the radius of the inscribed circle.
Given that, Area
=
154
c
m
2
⇒
π
r
2
=
154
⇒
r
=
7
c
m
Let a be the side and h height of the triangle. From properties of an equilateral triangle, we know that the point O divides AD in the ratio 2:1.
So,
r
=
h
3
⇒
h
=
3
r
=
21
c
m
Now, altitude,
h
=
√
3
2
a
⇒
a
=
2
h
√
3
=
42
√
3
=
14
√
3
c
m
Hence, perimeter
=
3
a
=
3
×
14
√
3
c
m
=
72.7
c
m
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