Math, asked by nibedan2483, 10 months ago

The area of circular playground is 22176cm2. Then find the cost of fencing this ground at the rate of rupes 50/m

Answers

Answered by DineshKharah
2

\pi {r}^{2}  = 22176 \\  {r }^{2}  =22176 \times 7 \div 22 \\  {r}^{2}   = 7056 \\ r = 84
The ground will be fenced from the exterior
i.e. it's circumference

circumference =2 \pi \times r
circumference = (approximately) 527.7875658031

Hope it is helpful.
If it is then mark me brainliest.
Answered by VelvetBlush
4

Let the radius of the circular playground = r m

Given,

area of the circular playground = \sf{{22176m}^{2}}

\longrightarrow \sf{π{r}^{2}=22176}

\longrightarrow\sf{{r}^{2}  =  \frac{22176 \times 7}{22}  = 7056}

\therefore \sf{r = √7056 = 84m}

Length of the fence = circumference = 2πr

\longrightarrow\sf{2 \times  \frac{22}{7}  \times 84}

\longrightarrow{\boxed{\sf{528m}}}

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