Question

The area of cross section of a pipe is 5.4cm^2 and water is pumped out of it at the rate of 27km/h . Find in litres the volume of water which flows out of the pipe in one minute

Answer 1

The area of cross section of pipe is =5.4cm^2
Speed of water =27kmph=27000/60=450m/min or 45000cm/min
Now water passes through the cross section =5.4*45000=2430000cm^3
Or 24300m^3/min
Now we know that 1m^3=1000ltr
So water release per min =24300000 ltr/min
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Answer 2

Answer:

Water release per min is 24300000 L/min.

Step-by-step explanation:

Given : The area of cross section of a pipe is 5.4 cm² and water is pumped out of it at the rate of 27 km/h .

To Find : In liters the volume of water which flows out of the pipe in one minute ?

Solution :

The area of cross section of pipe is = 5.4 cm²

Speed of water =27 km/h

Converting km/h into cm/min,

$27\ km/hr=\frac{27000}{60}\ m/min=450\ m/min$

$27\ km/hr=45000\ cm/min$

Now water passes through the cross section is given by,

$W=5.4\times 45000=2430000\ cm^3/min$

$W=24300\ m^3/min$

We know that,  $1\ m^3=1000\ L$

Water release per min is 24300000 L/min.