Question

the area of equilateral triangle is 64 x 3 square root CM square find the length of each of a triangle

Answer 1

hello friend!!!!

here is ur answer!!!!
\begin{lgathered}area \: of \: equilateral \: triangle = ( \sqrt{3} \div 4) {side}^{2} \\ 64 \sqrt{3} = ( \sqrt{3} \div 4) {side}^{2} \\ 64 \sqrt{3} \times (4 \div \sqrt{3} ) = {side}^{2} \\ \sqrt{3} \: canceled \\ 64 \times 4 = {side}^{2} \\ 256 = {side}^{2} \\ side = \sqrt{256} \\ side = 16cm\end{lgathered}areaofequilateraltriangle=(3​÷4)side2643​=(3​÷4)side2643​×(4÷3​)=side23​canceled64×4=side2256=side2side=256​side=16cm​
I hope you will understand

Answer 2

$\mathsf{Area \: of \: the \: equilateral \: triangle = \dfrac{ \sqrt{3} }{4}\times side^{2}}$


In the question area of the equilateral triangle is 64√3 cm² , therefore √3 / 4 × side² will be equal to 64√3 cm².



$\mathsf{ \dfrac{ \sqrt{3}} { 4 } \times {side}^{2} = 64 \sqrt{3} c {m}^{2} } \\ \\ \\ \mathsf{ \sqrt{3} \times \frac{1}{4} \times side {}^{2} = 64 \times \sqrt{3} { \: cm}^{2} }$


$\mathsf{ \dfrac{1}{4} \times {side}^{2} = 64 \: cm {}^{2} } \\ \\ \\ \mathsf{ {side}^{2} = 64 \times 4 \: cm { }^{2} } \\ \\ \mathsf{side = \sqrt{4 \times 64 \: c {m}^{2}} }$

$\mathsf{side = 2 \times 8 \: cm} \\ \\ \mathsf{side = 16\: cm}$




$\mathsf{Therefore \: length \: of \: each \: of \: the \: side} \\ \mathsf{ of \: the \: equilateral \: triangle \: is \: 16 \: cm.}$