the area of four walls is 192 m sq. the breadth and height of the room are 10m and6m respectively. find the length of room
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192=2(L+B)×h
192=2(L+10)10
192=(2L+20)10
192=20L+200
20L=8
l=8/20
192=2(L+10)10
192=(2L+20)10
192=20L+200
20L=8
l=8/20
arpit9939:
answer is 6 cm
Answered by
7
Given,
For the room
Area of the four walls = 192 m^2
Breadth = 10 m
Height = 6 m
Let the length be L m.
We know that
Area of four walls = 2H (L + B)
=> 192 = 2 × 6 (L + 10)
=> 192 = 12 (L + 10)
=> 192 = 12L + 120
=> 192 - 120 = 12L
=> 72 = 12L
=> L = 72/12
=> L = 6
•°• The length of the room is 6 m.
For the room
Area of the four walls = 192 m^2
Breadth = 10 m
Height = 6 m
Let the length be L m.
We know that
Area of four walls = 2H (L + B)
=> 192 = 2 × 6 (L + 10)
=> 192 = 12 (L + 10)
=> 192 = 12L + 120
=> 192 - 120 = 12L
=> 72 = 12L
=> L = 72/12
=> L = 6
•°• The length of the room is 6 m.
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