the area of four walls of a room is 120 m square if the length of the room is twice its breadth and the height is 4 m find the area of the floor
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Lateral surface area = 120m²
let the breadth be x
length = 2x
height = 4m
Lateral surface area = 2 h ( l + b )
120 = 2×4( x +2x )
![\frac{120}{8} = 3x \frac{120}{8} = 3x](https://tex.z-dn.net/?f=+%5Cfrac%7B120%7D%7B8%7D++%3D+3x)
3x = 15
![x = \frac{15}{3} x = \frac{15}{3}](https://tex.z-dn.net/?f=x+%3D++%5Cfrac%7B15%7D%7B3%7D+)
x = 5
length = 2x = 2 × 5 = 10m
breadth = x = 5m
area of the floor = length × breadth
= 10m × 5m
= 50m²
let the breadth be x
length = 2x
height = 4m
Lateral surface area = 2 h ( l + b )
120 = 2×4( x +2x )
3x = 15
x = 5
length = 2x = 2 × 5 = 10m
breadth = x = 5m
area of the floor = length × breadth
= 10m × 5m
= 50m²
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