Question

The area of four walls of a room is 150 M2 IF THE LENGTH OF THE ROOM IS TWICE ITS BREADTH AND THE HEIGHT IS 4M FIND THE AREA OF THE FLOOR

Answer 1

let breadth of the room= b=x m
length=l=2x m
height=h=4m
given area of the four walls=150m^2
2(l+b)h=150
2(2x+x)*4=150
8*3x=150
x=150/24
x=35/4
therefore
b=x=35/4m
l=2x=(2*35/4)m=35/2m
area of the floor=lb
=35/2*35/4
=1225/8 sq m

Answer 2

Given:-

• Area of four walls of a room is 120m².
• The length is twice the breadth.
• Height of the room is 4m.

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To find:-

• Breadth of the room.

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Solution:-

Let the breadth of the room be b.

Then,

Length of the room will be 2b.

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Note:- Area of four walls means the lateral surface area of the room.

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★ Therefore, we will use the formula of lateral surface area of cuboid.

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$\boxed{\tt{\bigstar{LSA_{(Cuboid)} = 2(l + b) \times h{\bigstar}}}}$

★LSA

(Cuboid)

=2(l+b)×h★

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Here

l = length

b = breadth

h = height

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$\tt:\implies\: \: \: \: \: \: \: \: {LSA = 120}:$

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$\tt:\implies\: \: \: \: \: \: \: \: {2(l + b) \times h = 120}:$

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$\tt:\implies\: \: \: \: \: \: \: \: {2(2b + b) \times 4 = 120}$

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$\tt:\implies\: \: \: \: \: \: \: \: {2(3b) = \dfrac{120}{4}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {6b = 30}:⟹6b=30$

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$\tt:\implies\: \: \: \: \: \: \: \: {b = \dfrac{30}{6}}$

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$\bf:\implies\: \: \: \: \: \: \: \: {b = 5}:⟹b=5$

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Hence,

The breadth of the wall is 5m.

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