The area of four walls of a room is 180 m^2. If the sum of its length and breadth is 10 m, find the height.
akhaleshgujjar2465:
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Answers
Answered by
31
Step-by-step explanation:
Answer
Let Length=l,breath=b,height=h
Area of four walls = 2h(l+b) = 108m
2
h:l=2:5,h:b=4:5 (Given)
∴h:l:b=4:10:5
Let h=4x,l=10x,b=5x
Now, the area of four walls, 2×4x(15x)=108
x
2
=
120
108
Then the area of the floor is l×b=10x×5x=50x
2
=50×
120
108
=45m
2
Answered by
1
Answer:
ANSWER
It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.
Area of four walls of the room is: 2h(l+b)
A=2h(l+b)=2×3(8+5)=6×13=78 m
2
Area of the ceiling is:
A=l×b=8×5=40 m
2
Total area of the four walls and the ceiling of the room is 78+40=118 m
2
It is given that cost of white washing is Rs.15/m
2
, therefore,
Total cost of white washing is:
118×15=1770
Hence, the cost of white washing the walls is Rs.1770.
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