Question

The area of four walls of a room is 240cm^2 and it's height is 10cm. Find the perimeter of the floor? Plss answer it fast guys​

Answer 1

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Given :

• Area of four walls (C.S.A) = 240 cm²
• Height (h) = 10 cm

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To Find :

• Perimeter of floor

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Solution :

Use formula for C.S.A of Cuboid :

$\large{\boxed{\sf{C.S.A \: = \: 2(l \: + \: b) h}}} \\ \\ \implies {\sf{2(l \: + \: b) \: \times \: 10 \: = \: 240}} \\ \\ \implies {\sf{2(l \: + \: b) \: = \: \dfrac{240}{10}}} \\ \\ \implies {\sf{Perimeter \: = \: 24}} \\ \\ \underline{\sf{\therefore \: Perimeter \: is \: 24 \: cm}}$

Answer 2

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Problem:-}}}}}}$

The area of four walls of a room is 240cm^2 and it's height is 10cm. Find the perimeter of the floor? Plss answer it fast guys

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$

Given :

Area of four walls = 240 cm²

Height (h) = 10 cm

_______________________

To Find :

Perimeter of floor

_______________________

Solution :

We can Use formula for C.S.A of Cuboid :

=> C.S.A = 2 ( l + b ) h

=> 2(l+b)×10=240

=> 2(l+b)= 240/10

∴ Perimeter=24

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