Math, asked by matangidevi198597, 3 months ago

The area of four walls of a room is 53 m2

. If room is 18 m long and 8.5 m wide, find:

(i) height of the room.

(ii) cost of tiling floor @ ₹ 200 per sq m.

(iii) cost of plastering walls and roof @ ₹ 100 per sq m.

(iv) amount of air it holds.​

Answers

Answered by yuup10
6

It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.

Area of four walls of the room is: 2h(l+b)

A=2h(l+b)=2×3(8+5)=6×13=78 m2

Area of the ceiling is: 

A=l×b=8×5=40 m2

Total area of the four walls and the ceiling of the room is 78+40=118 m2

It is given that cost of white washing is Rs.15/m2, therefore,

Total cost of white washing is:

118×15=1770

Hence, the cost of white washing the walls is Rs.1770.

Answered by debanujBoro
0

Step-by-step explanation:

ii) cost of tilling floor is ruppes 250 per sq m

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