Question

the area of four walls of a room is 57.4 metre square if the room is 5 metre long and 3.2 metre wide find the length of the room​

Answer 1

• Answer -

h = 3.5 m

•Explation -

LSA = 57.4 sq.m

L= 5 m B = 3.2 m

•Solution -

Lateral surface area of the room is

LSA = 21h + 2bh

LSA = 2h (l + b)

57.4 = 2×h(5 + 3.2)

$\frac{57.4}{2}= h × 8.2$

h =$\frac{28.7}{8.2}$

h = 3.5 m

Hence , the height of the room is 3.5 m .

Answer 2

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The area of four walls of a room is 57.4 metre square if the room is 5 metre long and 3.2 metre wide find the height of the room.

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➡Height of room is 3.5m

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• L.S.A of room = 57.4m²
• Length of room = 5m
• Breadth of room = 3.2m

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• Height of room = ?

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L.S.A of cuboid =

$\bf \pink{2(l + b)h}$

$\bf {\underline {\underline{✤ SƠԼƲƬƖƠƝ}}}$

$\bf L.S.A \: of \: cuboid =57.4 {m}^{2}$

$\bf \implies 57.4 = 2(5 + 3.2) \times h$

$\bf \implies 57.4 = 2 \times 8.2 \times h$

$\bf \implies 57.4 = 16.4 \times h$

$\bf \implies 16.4 \times h = 57.4$

$\bf \implies h = 57.4 \div 16.4$

$\bf \implies h = 3.5m$

Therefore, Height of room is 3.5m.

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