the area of isosceles triangle is 48 cm find the perimeter of the triangle if its an equal side is 12 cm long
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Method 1: Use Heron's Formula
Area = √[s(s-a)(s-b)(s-c)]
where s = (a+b+c)/2
And Perimeter of triangle is equal to Sun of its sides = a + b + c = 2s
Now using Heron's Formula find "s".
Area is given (= 48 cm²), & try sides say a, b are given (a=b=12cm).
Find "C" or "S".
Method 2:
Use Area = 1/2 (base)(height)
Take any of the given equal sides as base(=12cm)
And then find height.
After that use Pythagoras to find the 3rd side (say "c").
Perimeter = ( 12 + 12 + c )cm
= ( 24 + c ) cm
Thankyou!!!
Area = √[s(s-a)(s-b)(s-c)]
where s = (a+b+c)/2
And Perimeter of triangle is equal to Sun of its sides = a + b + c = 2s
Now using Heron's Formula find "s".
Area is given (= 48 cm²), & try sides say a, b are given (a=b=12cm).
Find "C" or "S".
Method 2:
Use Area = 1/2 (base)(height)
Take any of the given equal sides as base(=12cm)
And then find height.
After that use Pythagoras to find the 3rd side (say "c").
Perimeter = ( 12 + 12 + c )cm
= ( 24 + c ) cm
Thankyou!!!
lalit646:
plz do full I didn't understood
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