Physics, asked by Krishana3774, 9 months ago

The area of one end of a U- tube is 0.01 metre square and that of the other end is 1 metre square .when a force was applied on the liquid at the fast and the force experienced at the other end is 20000 N. What is the force applied on the liquid at the first end?

Answers

Answered by nirman95
39

Given:

The area of one end of a U- tube is 0.01 metre square and that of the other end is 1 m². When a force was applied on the liquid at the 1st end, the force experienced at the other end is 20000 N.

To find:

Force applied at the 1st end.

Calculation:

Pascal's Law states that the pressure exerted by fluid will be same at all points at a specified depth.

Hence,

  \sf{\therefore \: P1 = P2}

 \sf{ =  >  \:  \dfrac{f1}{a1}  =  \dfrac{f2}{a2} }

 \sf{ =  >  \:  \dfrac{f1}{0.01}  =  \dfrac{20000}{1} }

 \sf{ =  >  \:  \dfrac{f1}{ {10}^{ - 2} }  =  \dfrac{20000}{1} }

 \sf{ =  >  \:  f1=  20000 \times  {10}^{ - 2} }

 \sf{ =  >  \:  f1=  200 \: N }

So, the force exerted at the first end is 200 N.

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