The area of parallelogram ABCD is 36cm2 .calculate the height of parallelogram ABEF if AB=4.2 cm
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area of a parallelogram=base*height
base(AB)=4.2cm
then,AB*height=36cmsq.
then,4.2*height=36
then,h=36/4.2
then,h=60/7cm
therefore,the height of the parallelogram ABCD is 60/7cm
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base(AB)=4.2cm
then,AB*height=36cmsq.
then,4.2*height=36
then,h=36/4.2
then,h=60/7cm
therefore,the height of the parallelogram ABCD is 60/7cm
HOPE THIS HELPED YOU
THANKS
Answered by
7
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here is your answer...
It is given that Area of parallelogram ABCD =36cm^2
AB = 4.2 cm
Let the height of Parallelogram ABEF = h
Area of parallelogram ABCD = Area of parallelogram ABEF
(THEY ARE IN THE SAME BASE AB AND BETWEEN THE SAME PARALLELS )
Therefore area of ABEF = 36cm2
Area of a parallelogram is = b x h
36 = 4.2 x h
h = 36 / 4.2
h = 8.57
THEREFORE THE HEIGHT = 8.57 CM
HOPE IT HELPS
FOLLOW ME ✌
here is your answer...
It is given that Area of parallelogram ABCD =36cm^2
AB = 4.2 cm
Let the height of Parallelogram ABEF = h
Area of parallelogram ABCD = Area of parallelogram ABEF
(THEY ARE IN THE SAME BASE AB AND BETWEEN THE SAME PARALLELS )
Therefore area of ABEF = 36cm2
Area of a parallelogram is = b x h
36 = 4.2 x h
h = 36 / 4.2
h = 8.57
THEREFORE THE HEIGHT = 8.57 CM
HOPE IT HELPS
FOLLOW ME ✌
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