Math, asked by sumansharma83788, 3 months ago

the area of parallelogram ABCD with AB =40cm and the corresponding altitude DE= 18cm is equal to that of another parallelogram PQRS with side QR=36cm find the altitude of this parallelogram corresponding to the side q ​

Answers

Answered by Hardik9061102040010
16

Step-by-step explanation:

let x be the altitude of parallelogram pqrs

40× 18 = 36 × x

x = 40× 18 /36

x= 20 cm

Answered by xXBangtanGirlXx
24

VERIFIED ANSWER:-

Given Data:-

Area of the parallelogram ABCD = Area of the parallelogram PQRS

For Parallelogram ABCD, base AB = 40 cm

Altitude DE = 18 cm

For Parallelogram PQRS, Side or Base QR = 36 cm

Find the corresponding altitude to the side QR of the parallelogram PQRS

Area of the Parallelogram = base × Height (Square units)

Area of the parallelogram ABCD = 40 × 18

Area of the parallelogram ABCD = 720 cm²

Area of the parallelogram PQRS = Area of the parallelogram ABCD

Base × Height = 720 cm²

36 cm × Height = 720 cm²

height =  \frac{720}{36} cm

Height = 20 cm

Therefore the corresponding altitude to the side QR for a parallelogram is 20 cm when the area of the parallelogram PQRS is equal to area of the parallelogram ABCD with base AB 40 cm and corresponding altitude DE 18 cm.

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