The area of parallelogram is 338 m2 its altitude is twice its corresponding base.find
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let base to de X m
then altitude = 2x..
according to the question
Are of llgm = base × height
338 =X × 2X
338=2X^2
169 = x^2
so. x = 13
hence base is 13 m and height is 26m
then altitude = 2x..
according to the question
Are of llgm = base × height
338 =X × 2X
338=2X^2
169 = x^2
so. x = 13
hence base is 13 m and height is 26m
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