The area of parallelogram is p cm2 and its height is g cm. A second parallelogram has equal but it's base is r cm more than that of the first. Obtain an expression in terms of p,q and r for the height h of second parallelogram
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Step-by-step explanation:
area of 1st parallelogram = y cm square, height = h cm
Area= Base\times Height
y=b×h ----eq 1
Base =b=y/h
area of 2nd parallelogram = 2y cm square, height = H cm
Base of 2nd parallelogram =
h
y
+x
2y=(
h
y
+x)×H
H=
(y+hx)
2yh
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