two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that < PTO= <OPQ
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Step-by-step explanation:
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hi mate here's ur answer.....pls refer to my attached file
Step-by-step explanation:
In trianglePTO & triangleOPQ
OP=OQ (Radii of the circle)
OT=OT (COMMON )
angleOPT = angleOQT (90degree)
therefore by RHS both triangles are congruent
therefore anglePOQ = angle
POT (by cpct)
....hence proved....
HAAASSHHH santi ab
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