Question

the area of path is 6500 m square find the cost of covering it with gravel 14 cm deep at the rate of ₹5. 60 per cubic metre

Answer 1

Area of the path = 6500 sq. m
Depth of gravel = 14 cm
= 0.14 m
Volume of gravel used = 0.14*6500 cubic m
Therefore cost of gravel = 0.14*6500*5.60
= Rs. 5096

Answer 2

The cost of covering the path with gravel is ₹509600.

• Volume is a mathematical term used to describe how much three-dimensional space an item or closed surface occupies. The area that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.
• Various forms have various volumes. Cubic units are used to quantify a solid's volume. For instance, the volume will be given in cubic metres if the dimensions are given in metres. The International System of Units uses this as the reference unit for volume (SI). Cubic meters, cubic feet, cubic inches, etc. are additional volume units.

Here, according to the given information, we are given that,

The area of the path = 6500 m².

The depth of the gravel = 14 cm.

Then, volume = Area × depth = $6500.(14) = 91000$ cm³.

Now, 1 cm³ costs ₹5. 60.

Then, 91000 cm³ costs ₹$(91000.(5.60))$ = ₹509600.

Hence, the cost of covering the path with gravel is ₹509600.

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