Question

the area of rectangle is 102 sqcm.if it's length is 17 cm ,what is its perimeter ?

Answer 1

Hey area of rectangle=l*b
so.17*b=102
b=102/17
b=6cm

So perimeter=2(17+6)
=2(23)
=46cm..


HOPE IT HELPS...

Answer 2

heya......

In the question....

●Given____


In a rectangle...
area = 102sqcm
length = 17cm

●To find ...
it's perimeter.

●Solution...

◆area of rectangle = length(l) × breadth(b)

just put values...

102sqcm = 17 × breadth..

102/17 = 6 cm

now
◆ perimeter of the rectangle=2( l +b )
2 (17+6) = 2×23 = 46cm...


thus..

the perimeter of the rectangle is 46cm



hope this helps!!!!