The area of rectangle is 192 cm^2 and its perimeter is 56 cm. Find the dimensions of the rectangle.
Answers
Answer:
l= 12 cm, b= 16 cm
OR
l= 16 cm, b= 12 cm
Step-by-step explanation:
Given: Area of rectangle= 192 cm^2
l*b= 192 cm^2 -(1)
Perimeter of rectangle= 56 cm
2(l+b)= 56 cm -(2)
From (1)
value of l= 192/b -(3)
putting this value of l in (2)
2(l+b)=56 cm
2(192/b+b)=56 cm
(192+b^2)/b= 56/2
192+ b^2=28b
b^2-28b+192=0
b^2-12b-16b+192=0
b(b-12) - 16(b-12)=0
(b-12)(b-16)=0
b=12,16
substituting value of b in (3)
If b= 12 cm
l= 192/12
l= 16 cm
If b= 16 cm
l= 192/16
l= 12 cm
Answer:- Length and breadth of rectangle are 16 cm and 12 cm respectively.
