Question

the area of rectangle is 270 cm and its length is 18 cm find
its breadth and
its perimeter​

Answer 1

Given :-

The area of a rectangle is 270 cm² and it's length is 18cm.

To Find :-

The breadth and the perimeter of the given rectangle respectively.

Used Concepts :-

• Area of a rectangle i.e " l × b " , where l is length and b is breadth of the rectangle.
• Perimeter of a rectangle i.e 2 × ( l + b ) , where l and b stands for as the same as the above .

Solution:-

Let , The Length of the rectangle = l = 18 cm

The breadth of the rectangle = b = ?

Area ( A ) of the rectangle = 270 cm²

Now , According to the question ,

l × b = A

18 × b = 270

b = 270/18

b = 15 cm

Now. , Perimeter of the rectangle = 2 × ( l + b )

2 × ( 18 + 15 )

2 × 33

66 cm

Therefore , the Breadth and perimeter of the rectangle are 15cm and 66cm respectively.

Answer 2

• Perimeter = 66 cm

• Breadth = 15 cm

Step-by-step explanation:

Given:-

• Area of Rectangle = 270 cm²
• It's Length = 18 cm

To Find:-

• It's Breadth
• It's Perimeter

Formula used:-

• Area of Rectangle = L × B
• Perimeter of Rectangle = 2(l + b)

Solution:-

Firstly,

$Area \:of\: Rectangle \:= \:L × B$

$270 \:= \:18 × B$

$B \:= \:\dfrac{270}{18}$

${\boxed{\red{B \:= \:15\:cm}}}$

Now,

$Perimeter\: of \:Rectangle \:= 2(l + b)$

$Perimeter \:= 2(18+ 15)$

$Perimeter\:= 2×33$

${\boxed{\red{Perimeter\:= 66\:cm}}}$

Hence, The Breadth and Perimeter of the given Rectangle is 15 cm and 66 cm respectively.

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