Question

the area of rectangluar room whose length and breadth are in ratio of5:3 is 735m2,then find the perimeter​

Answer 1

$\huge\mathbb{\underline{\underline{\red{SOLUTION:-}}}}$

$\bold{Given}\begin{cases}\sf{length:breadth=5:3}\\ \sf{Area=735m{}^{2}}\end{cases}$

• Let length and breadth be x

• Then it's 5x and 3x

Now :-

$\bf{\underline{\underline{\purple{According\:To\: Question:-}}}}$

$\tt{\red{ Area\:of\: rectangle=Length\times Breadth}}$

$\begin{cases}\sf{Length=5x}\\ \sf{Breadth=3x}\\ \sf{Area=735m{}^{2}}\end{cases}$

$\sf Area\:of\: rectangle=L\times B\\ \\ \sf\longrightarrow 735=5x\times 3x\\ \\ \sf\longrightarrow 735=15x{}^{2}\\ \\ \sf\longrightarrow \frac{\cancel{735}}{\cancel{15}}=x{}^{2}\\ \\ \sf\longrightarrow 49=x{}^{2}\\ \\ \sf\implies \sqrt{49}=x\\ \\ \sf\implies x=7cm$

$\sf{\blue{The \:value \:of\: x\: is \:7cm}}$

●Now the length

=7×5=35cm

●And the breadth

=7×3=21cm

$\bf{\pink{ length =35cm\:breadth=21cm}}$

We have to find the perimeter

Now :-

$\bf Perimeter\:of\: rectangle=2(L+B)\\ \\ \sf\implies perimeter=2(35+21)\\ \\ \sf\implies perimeter=2\times 56\\ \\ \sf\implies perimeter=112cm$

The perimeter of rectangular room is 112cm

#BAL

#answerwithquality

Answer 2

$\underline \mathbb{SOLUTION}$

$\underline \mathbb{GIVEN}$

LENGTH : BREADTH = 5 : 3

$area = 735 {m}^{2}$

$\underline \mathbb{LET}$

THE LENGTH AND BREADTH BE X.

THEN IT CAN BE WRITTEN AS 5X AND 3X.

$\underline \mathbb{NOW}$

$\underline \mathbb{ATQ,}$

$= > area \: of \: rectangle$

$= length \times breadth$

Length= 5x

Breadth=3x

$area = 735 {m}^{2}$

Area of rectangle = L×B

$= > 735 = 5x \times 3x$

$= > 735 = 15 {x}^{2}$

$= > \frac{735}{15} = {x}^{2}$

${x}^{2} = 49$

$x = \sqrt{49}$

$x = 7cm$

$\underline \mathbb{NOW,}$

LENGTH=7×5 = 35 cm

BREADTH = 7×3 = 21 cm

WE HAVE TO FIND THE PERIMETER,

$\underline \mathbb{NOW,}$

$perimeter = 2(35 + 21)$

$perimeter = 2 \times 56$

$perimeter = 112cm$

HENCE,

THE PERIMETER OF RECTANGLE IS 112 cm.

#BAL

#Answerwithquality