Question

The area of rectangular garden 50m long is 300m . find preminter of garden​

Answer 1

p = 2 (l + w)

= 2 (50 + 300)

= 2 (350)

= 700m. ....ans

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Answer 2

Diagram:

$\setlength{\unitlength}{0.25cm}\begin{picture}(5,5)\thicklines\multiput(0,0)(24,0){2}{\line(0,1){7}}\multiput(0,0)(0,7){2}{\line(1,0){24}}\put(0, - 1){\sf{A}}\put(23, - 1){\sf{B}} \put(23,7.1){\sf{C}} \put(0,7.1){\sf{D}} \put(10,-2){\sf{50\ m}} \put(5,2){ \sf @ABHI } \end{picture}$

Given:

• Length of Rectangular Garden = 50m
• Area of Rectangle = 300m²

Find:

• Perimeter of Garden

Solution:

we, know that

$\boxed{ \rm Area \: of \: rectangle = l \times b}$

Where,

• Area of Rectangle = 300m²
• Length, l = 50m

So,

$\dashrightarrow\rm Area \: of \: rectangle = l \times b$

$\dashrightarrow\rm 300 = 50\times b$

$\dashrightarrow\rm \dfrac{300}{50} = b$

$\dashrightarrow\rm b = 6m$

$\rule{300}{2}$

we, know that

$\boxed{ \rm Perimeter \: of \: rectangle = 2(l + b)}$

where,

• Length, l = 50m
• Breadth, b = 6m

So,

$\dashrightarrow\rm Perimeter \: of \: rectangle = 2(l + b)$

$\dashrightarrow\rm Perimeter \: of \: rectangle = 2(50 + 6)$

$\dashrightarrow\rm Perimeter \: of \: rectangle = 2(56)$

$\dashrightarrow\rm Perimeter \: of \: rectangle = 112 {m}^{2}$

Hence, Perimeter of Rectangular garden will be 112m²