The area of rhombus is 144cm² and one of its diagonals is double the other. The length of the longer diagonal is.
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Step-by-step explanation:
Consider Rhombus ABCD with long diagonal AC and short diagonal BD.
Area is 144cm^2 and the diagonals intersect at E.
EC =1/2AC and ED=1/2BD
Arbitrarily choose any of the 4 triangles bounded by ABCD hiving a right vertex at E. They are all congruent
I chose triangle DEA. Area of which is 1/2(ED x EC)= 36 or 1/4 total area of rhombus.
If EC =2ED then 1/2(ED)(2ED)= 36 and ED=6
Therefore BD= 12 and AC=24cm.
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