the area of rhombus is 40 centimetre square and its perimeter is 20 cm what is its height
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Hey mate..
========
We have,
Perimeter of a rhombus ABCD = 20cm
We know,
Perimeter of a rhombus ABCD = 4 × Side
Let, Each side be the base of the rhomus.
Now,
=> 20 = 4 × Side
=> 5 = Side
I.e. AB = BC = CD = AD = 5cm
Now,
In right Angled triangle ABD we have,
BD^2 = AD^2 + AB^2
= (5)^2 + (5)^2
= 25 + 25
= 50
Thus, BD = Height of the rhombus =
Hope it helps !!!!
========
We have,
Perimeter of a rhombus ABCD = 20cm
We know,
Perimeter of a rhombus ABCD = 4 × Side
Let, Each side be the base of the rhomus.
Now,
=> 20 = 4 × Side
=> 5 = Side
I.e. AB = BC = CD = AD = 5cm
Now,
In right Angled triangle ABD we have,
BD^2 = AD^2 + AB^2
= (5)^2 + (5)^2
= 25 + 25
= 50
Thus, BD = Height of the rhombus =
Hope it helps !!!!
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