Question

the area of rhombus is 48 CM square and its perimeter is 20 cm what is its height

Answer 1

perimeter=20cm
4*side of rhombus=20cm

side of the rhombus=20/4
side =5cm
area=1/2* base *height
48=1/2*5*height
height=48*2/5
therefore,
height =19.2

Answer 2

Given:

• The area of rhombus = 48 $cm^2$
• The perimeter of rhombus = 20 cm

To Find:

• The value of its height.

Solution:

A rhombus consists of four sides, let "4A" represent the sides of a rhombus.

The value one side of a rhombus is,

4A = 20 {perimeter = sum of all four sides}

A = 20/4 = 5 cm {base of the rhombus}

We know that,

Area = 1/2 × h × b → {equation 1}

Where "h" is the height and "b" is the base.

Now rearrange equation 1 in terms of height. We get,

h = (2 × area)/b

On substituting the given values in the above equation we get,

h = (2×48)/5 {multiplying terms in numerator}

h = 96/5 = 19.2 cm {dividing the terms}

∴ The height of the rhombus = 19.2 cm