Question

the area of rhombus is 96 cm². If its one diagonal is 12 cm, find the length of its side​

Answer 1

Step-by-step explanation:

Hope this is helpful. Refer to the above screenshot for step by step explanation.

A = Pq/2

q = 4a

a = √P² + q²/2

P = √2P² + 4(A/P)²

= 2√12² + 4(96/12)²

40cm

Answer 2

Given :-

• Area of Rhombus = 96cm²
• One Diagonal of the Rhombus = 12cm

To Find :-

• Length of its Side .

Solution :-

★ Area of the Rhombus ★

⇒ Area = ½ × Product of Diagonal

⇒ 96 = ½ × 12 × Diagonal

⇒ 96 = 6 × Diagonal

⇒ 96/6 = Diagonal

⇒ 16 = Diagonal

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★ Side of the Rhombus ★

⇒ Side = ½ × √(Diagonal)² + (Diagonal)²

⇒ Side = ½ × √(12)² + (16)²

⇒ Side = ½ × √144 + 256

⇒ Side = ½ × √400

⇒ Side = ½ × 20

⇒ Side = 10cm

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So, Side of Rhombus is 10cm

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