The area of Right angled triangle is 600 cm. If the base of
the triangle exceeds the altitude by 10 cm , Find the
dimensions of the triangle.
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Answer:
altitude = 30cm and base = 40cm
Step-by-step explanation:
let the triangle be ABC with base BC right angled at B.
ar = 600cm^2
altitude = AB = a
base = BC = a+10
in triangle ABC,
1/2BH =ar
1/2*a*a+10 = 600cm^2
a^2 + 10a = 1200
a^2 + 10a - 1200 = 0
a^2 +40a -30a - 1200 = 0
a (a+40) - 30 (a+40) = 0
(a-30)(a+40) = 0
a=30 and a=-40
but as distance cannot be negative, so a= altitude =30cm
and base = a+10 = 40 cm
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