the area of right angled triangle is 96 m^2. if the base is three times its altitude ,find the base
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height is 8 and base is 24
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Let length of altitude = x (height)
Base= 3x
Area of right angled triangle = 1/2 b*h
96=1/2 3x*x
96*2= 3x^2
192= 3x^2
X^2= 192/3
X^2=64
X=8
Base= 3*8=24
Base= 3x
Area of right angled triangle = 1/2 b*h
96=1/2 3x*x
96*2= 3x^2
192= 3x^2
X^2= 192/3
X^2=64
X=8
Base= 3*8=24
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