The area of sector, whose arc length is 25 pie cm and the angle of the sector is 60°, will be?
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r=L/2π×360/θ
= 25π /2π × 360/60
= 25/2*6
=75 cm.
Area of sector = l×r/2=25π*75/2
= 1875/2 π
= 937.5 π
= 2946.4cm²
= 25π /2π × 360/60
= 25/2*6
=75 cm.
Area of sector = l×r/2=25π*75/2
= 1875/2 π
= 937.5 π
= 2946.4cm²
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