The area of square ABCD is 16 cm². Find the area of square joining the mid roints of the sides.
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Answer:
The diagonal length= √(4²+4²)= 4√2cm. The area of the small square = 2√2 × 2√2 =4×2= 8cm²
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2
Answer:
The area of square ABCD is 16 cm². The area of squares joining the mid points of the sides is 8cm².
Step-by-step explanation:
Given: The area of square ABCD is 16 cm².
Find the area of squares joining the midpoints of the sides.
Find the length of the side of the square by using its area.
The area of square = (side)²
(side)² = 16
The length of the side of a square= √16=4 cm
The diagonal length= √(4²+4²)= 4√2cm.
By midpoint theorem, the side made by joining the midpoints of the square = 1/2 of diagonal
Therefore side of small square = 4√2 /2 = 2√2cm
The area of the small square = 2√2 × 2√2 =4×2= 8cm².
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