Question

The area of square and rectangle are equal at 36 cm². What will we thw width of the rectangle if its length is 3cm more than side of the square

Answer 1

Area of square = 36cm²

We know,

area = side²
36 = side²

$side \: = \sqrt[]{36}$
side = 6cm


Let the width be ' b'

Given that its length is 3cm more than side of the square.

So, length = 6 + 3 cm = 9 cm


Area of rectangle = l × b

$36 = 9 \times b$

$b = \frac{36}{9}$

b = 4



So,

the width will be 4cm

Answer 2

Hi !!!

Here is your answer,

Given : -
Area of square = area of rectangle

Area of square = 36cm²
➡(side)² = 36
➡side = √36
➡side = 6

side of square = 6cm

(ATQ)
length of the rectangle is 3cm more than side of square.

length of rectangle = 3+6 = 9cm

Area of rectangle = 36
➡length*breadth = 36
➡9*breadth = 36
➡breadth = 36/9
➡breadth = 4

breadth (width) of rectangle = 4cm


Hope it helps.