Question

The area of the∆ABC is 36sqcm ofDEF are midpoints andAB,BC,AC respectively then area of∆DEF is

Answer 1

Area of ΔABC = 36 sq.cm

Area of ΔABC = 4 (area of ΔDEF)

Area of ΔDEF = ¼(area of ΔABC)

= ¼(36)

= 9 sq.cm

Hope it helps

Answer 2

Hi,

Please see the attached file!


Thanks