Triangle ABC is an equilateral triangle, the coordinates of B and C are (-3,0) and (3,0). Find the coordinates of A and area of triangle ABC
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you can draw a graph and find the third side with the help of third side you can find the coordinates of a and find height by measuring the perpendicular distance and the find area by formula 1/2*base*height
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AB =BC=AC
USING DISTANCE FORMULA
√(-3-x)^2 +(3-y)^2 =√(-3-3)^2+(0-0)^2
AB = BC ( AB^2=BC^2)
9-6x+x^2 + 9-6y+y^2 =36
18-6x-6y+x^2+y^2=36
x^2+y^2-6x-6y=18
similarly compare AC and BC
you will get the values of x and y
USING DISTANCE FORMULA
√(-3-x)^2 +(3-y)^2 =√(-3-3)^2+(0-0)^2
AB = BC ( AB^2=BC^2)
9-6x+x^2 + 9-6y+y^2 =36
18-6x-6y+x^2+y^2=36
x^2+y^2-6x-6y=18
similarly compare AC and BC
you will get the values of x and y
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