the area of the figure given below is
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Step-by-step explanation:
extend the line from C so that it can intersect the line ED
and the point of contact let say P
so now triangle pdc is a right triangle with perpendicular sides PC and PD
so area of the triangle PDC = 1/2* 5*4 = 10
and area of the rectangle EPBA is = 8*10=80
next figure is a hexagon which we can divide into 6 equilateral triangles with side 8cm
so area of the hexagon = 6* (√3/4)8*8
6*√*2*8
96√3
so add all the areas = 96√3+80+10= 96√3+90
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