Math, asked by ritikachwdhry9068, 6 months ago

The area of the parallelogram ABCD in which AB = 6.2 cm and the perpendicular from C on AB is 5 cm is
1 point
(a) 30 cm2
(b) 29 cm2
(c) 28 cm2
(d) 31 cm2​

Answers

Answered by Anonymous
18

Answer:

option c

have solved but not sure

Answered by chandujnv002
0

Answer:

The area of the parallelogram ABCD, where AB = 6.2 cm and C on AB is perpendicular, is The parallelogram's surface area 31.

Step-by-step explanation:

How do you find the area of a parallelogram?

$\mathrm{ABCD}$ is a parallelogram.

$\mathrm{CD} \| \mathrm{AB}$

$\therefore \mathrm{CD} \| \mathrm{AE} \quad$ [Extended part of parallel side ]

$\Rightarrow$ Area of parallelogram $\mathrm{ABCD}=\mathrm{AB} \times \mathrm{CE} \quad[$ Since, $\mathrm{CE}$ situated between same parallel lines ]

$$\begin{aligned}& =12 \times 6.2 \\& =744 \mathrm{~cm}^2\end{aligned}$$

The parallelogram's surface area

A = 6.2 * 5 = 31 cm^{2}

A parallelogram's area is equal to the parallelogram's product of its length and height. A quadrilateral has a total of 360 degrees in its internal angles. A parallelogram has two sets of equal-sized parallel sides. It has an area and a perimeter because it is a two-dimensional figure. A parallelogram is a unique form of quadrilateral in which the opposing sides are parallel and equal.

Therefore the correct answer is option (d) 31 cm2​

To learn more about parallelogram area refer to :

https://brainly.in/question/226189

https://brainly.in/question/49555906

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