Question

the area of the parallelogram ABCD is 63 CM2. the side of ab is 9 cm and height if FC is 5 cm .find the side AD and also the height corresponding to the side ab and also find the perimeter

Answer 1

we know that area of //gm is base*height..... area= 63, ab=dc=9 , ae*de= 63 ,ae=7cm. ad= 63/5=12.6cm. perimeter = 2(7+12.6)=39.2cm

Answer 2

The side AD = 12.6 cm and also the height corresponding to the side AB i.e., AE = 7 cm and also the perimeter of parallelogram ABCD is 39.2 cm.

Step-by-step explanation:

It is given that,

Area of the parallelogram ABCD = 63 cm²

Side AB = 9 cm

Height FC = 5 cm

We know that the opposite facing sides of the parallelogram are equal in length, so, we have  

AB = CD = 9 cm and AD = BC ….. (i)

Step 1: Finding the length of side AD

Considering the side AD as the base and height corresponding to AD is FC, therefore,

Area of parallelogram = base * height

⇒ 63 = AD * FC

⇒ 63 = AD * 5  

⇒ AD = 63/5

⇒ AD = 12.6 cm

∴ AD = BC = 12.6 cm …… (ii)

Step 2: Finding the height corresponding to the side AB i.e., length of AE

From (i), we will consider AB or CD as the base and the height corresponding to it AE, therefore,

Area of parallelogram = CD * AE  

⇒ 63 = 9 * AE

⇒ AE = 63/9

⇒ AE = 7 cm

Step 3: Finding the perimeter of the parallelogram ABCD

From (i) & (ii), we get

The perimeter of the parallelogram ABCD is given by,

= AB + BC + CD + DA

= 7 + 12.6 + 7 + 12.6

= 39.2 cm

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