Question

The area of the quadrilateral ABCD where AC = 22cm, BM = 3cm, DN = 3cm and BM AC ,DN AC A) 55 cm? B) 66 cm? C) 39 cm D) 89 cm?​

Answer 1

Step-by-step explanation:

Area of \Delta ABC=\frac{1}{2}\times b\times h=\frac{1}{2}\times22\times3=33cm^2

Area\ of\ \Delta ADC=\frac{1}{2}\times22\times3=33cm^2

Area of the quadrilateral ABCD

= Area of \Delta ABC+Area of \Delta ADC

=33cm^2+33cm^2=66cm^2

Hence, the required area= 66cm^2

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Answer 2

Answer:

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