Question

The area of the quadrilateral the coordinates of whose vertices are (1;-2) (6;2) (5;3) (3;4) are
pls solve this as fast as possible ☺​

Answer 1

Answer:

11.5 sq. units

Step-by-step explanation:

Area of quadrilateral = (1/2)*((x1−x3)(y2−y4)−(x2−x4)(y1−y3)) 

= (1/2)*((1-5)(2-4)-(6-3)(-2-3))

= (1/2)*(8-(-15))

= (1/2)*(23)

= 11.5