The area of the rectangular plot is 528 m square . The length off-the-wall plot ( in meters ) is one more than twice it's breadth.We need to find the length and breadth of the plot?
Answers
Answered by
4
Heya...
let the breadth =b m
length = l =(2b+1)m
area =528m²
l*b= 528
(2b+1)b-528=0
2b²+b-528=0
2b²+33b-32b-528=0
b(2b+33)- 16(2b+33)=0
(2b+33)(b-16)=0
2b+33=0 or b-16=0
b should not be zero
therefore
b-16=0
b=16
breadth = 16m
length =l= 2b+1=2*16+1=32+1=33m
let the breadth =b m
length = l =(2b+1)m
area =528m²
l*b= 528
(2b+1)b-528=0
2b²+b-528=0
2b²+33b-32b-528=0
b(2b+33)- 16(2b+33)=0
(2b+33)(b-16)=0
2b+33=0 or b-16=0
b should not be zero
therefore
b-16=0
b=16
breadth = 16m
length =l= 2b+1=2*16+1=32+1=33m
satish66:
thaks
Answered by
7
The area of the rectangular plot is 528 m²
Length = ¿?
Breadth = ¿?
Let's the breadth = b meter
Length = 2 [ breadth ] + 1
Length = ( 2b + 1 )m
Since :
( 2b + 1 ) × b = 528
2b² + b = 528
2b² + b - 528 = 0
Thus the required equation is :
2b² + b - 528 = 0
2b² - 32b + 33b - 528 = 0
2b ( b - 16 ) + 33 ( b - 16 ) = 0
( b - 16 ) ( 2b + 33 ) = 0
So : b = 16 m
And L ( length ) = 2b + 1
===> 2 ( 16 ) + 1
===> 32 + 1
===> 33m
Similar questions