Math, asked by satish66, 1 year ago

The area of the rectangular plot is 528 m square . The length off-the-wall plot ( in meters ) is one more than twice it's breadth.We need to find the length and breadth of the plot?

Answers

Answered by RabbitPanda
4
Heya...

let the breadth =b m
length = l =(2b+1)m
area =528m²

l*b= 528
(2b+1)b-528=0

2b²+b-528=0
2b²+33b-32b-528=0
b(2b+33)- 16(2b+33)=0
(2b+33)(b-16)=0
2b+33=0 or b-16=0

b should not be zero
therefore
b-16=0
b=16

breadth = 16m
length =l= 2b+1=2*16+1=32+1=33m

satish66: thaks
RabbitPanda: Wlcm
Answered by ItzLoveHunter
7

\boxed{\rm{\purple{︎︎︎Answer︎︎︎}}}

\huge\bold{given}

The area of the rectangular plot is 528 m²

\huge\bold{To find}

Length = ¿?

Breadth = ¿?

\huge\bold{Now:)}

Let's the breadth = b meter

Length = 2 [ breadth ] + 1

Length = ( 2b + 1 )m

Since : \huge\mathfrak\pink{Area = Length× Breadth}

( 2b + 1 ) × b = 528

2b² + b = 528

2b² + b - 528 = 0

Thus the required equation is :

\mathbb\blue{2b² + b - 528}

2b² + b - 528 = 0

2b² - 32b + 33b - 528 = 0

2b ( b - 16 ) + 33 ( b - 16 ) = 0

( b - 16 ) ( 2b + 33 ) = 0

So : b = 16 m

And L ( length ) = 2b + 1

===> 2 ( 16 ) + 1

===> 32 + 1

===> 33m

\mathbb\blue{b = 16m ....... L = 33m}

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