Question

The area of the sector of a circle with radius 6 cm and central angle 60 degree is​

Answer 1

$area = \frac{60}{360} \times \frac{22}{7} \times {6}^{2} \\ \\ = \frac{6 \times 22 \times 36}{36 \times 7} \\ \\ = 18.85 \: {cm}^{2}$

Answer 2

area is sector= theta/360*πr^2

theta= 60

r=6cm

area = 60/360*36π

=6π cm^2

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