Question

The area of the square park is the same as of a rectangular park. If the side of the square park is 60m and the length of the rectangular park is 90m find the breath of the rectangular park.

Answer 1

Side of Square Park = 60 m

Area of Square Park = (60)² = 3600 m²

Length of Rectangular Park = 90 m

Breadth of Rectangular Park = x m

Area of Rectangular Park = Length*Breadth

It is Given that :

Area of Square Park = Area of Rectangular Park

Therefore

3600 m² = Length × Breadth

3600 = 90 × x

x = 3600 / 90 = 40

x = 40 m

Breadth of Rectangular Park = x = 40 m

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Answer 2

$\sf{\large{\underline{Question:}}}$



The area of the square park is the same as of a rectangular park. If the side of the square park is 60m and the length of the rectangular park is 90m find the breath of the rectangular park.



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$\sf{\large{\underline{Answer:}}}$


Breadth = 40 m


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▶ Given,


Side of Square Park = 60 m
Length of Rectangular Park = 90 m


▶ To Find:


Breadth = ?


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$\mathfrak{\huge {\underline {\underline {Brainly \: Solution:}}}}$



$\green{\sf Area \: of \: Square \: park = {a}^{2}} \\ \\ \green{\sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 60 {}^{2} } \ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \green{ \sf = 3600 \: m {}^{2} } \\ \\ \\ \blue{ \sf \because Area \: of \: Square \: park = Area \: of \: Rectangular \: park \: \: \: \: \: \: \: \: \: \pink{.. (Given)}} \\ \\ \sf \blue{ \to \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3600 \: m {}^{2} = Length \times Breadth } \\ \\ \blue{ \to \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \sf 3600\: m {}^{2} = 90 \: m\times Breadth}} \\ \\ \blue{ \sf \to \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Breadth = \frac{ \cancel{3600} \: \: ^{ \large 40} \: m {}^{ \cancel2} }{ \cancel{90} \: \cancel m} }$

$\huge \orange{ \boxed{ \boxed{ \sf{ \therefore Breadth = 40 \: m}}}}$



✔✔ Hence, it is solved ✅✅.



$\huge \green{ \boxed{ \boxed{ \mathscr{THANKS}}}}$