Question

the area of the square parkas the same as the rectangular Park if the side of the square Park is 6 cm and the length of its rectangular Park is 90 M find the breadth of the rectangular Park

Answer 1

Area of a rectangle =s×s
=6×6
=36
Change 90m into cm=90×100=9000
Let the breath of the rectangle be x
Area of a rectangle=l×b
=9000×x=36
X=36/9000
X=250
Thefore the breadth of the rectangle is 250cm

Answer 2

$\: \: \color{blue}\huge \mathbb{ \star \: Hola! \: Mate \: \star}$
$\underline{\bf{SO/UTION}} : \: \\ \\ \tiny\bf{as \: we \: know \: the \: area \: of \: square > > \: that \: a \: side \: is \: given \: 6 \: cm} \\ \\ \tiny \bf{then, \: the \: area \: of \: square > > {s}^{2} } = {6}^{2} = 6 \times 6 = 36 \: cm. \\ \\ \tiny \bf{and \: the \:area \: of \: rectangular \: park \: is \: same \: as \: the \: area \: of \: square } \\ \\ \tiny\bf{the \: lenght \: of \: the \: rectangular \: park \: is \: 90 \: m \: so, \: first \: we \: will} \\ \tiny\bf{ convert \: it \: into \: cm} \: = > > 90 \times 100 = 9,000 \: cm \\ \\ \underline{\bf{then,}} \\ \\ \bf{we \: know \: the \: area \: of \: rectangle > > } \\ \\ \rightarrow \: \huge (l \times b) \\ \\ \rightarrow \: \frak{ 36 =9000 \times b } \\ \\ \rightarrow \: \frak{b = \frac{36}{9000} = 0.004 \: cm } \\ \\ \tiny\bf{now \: l = 9000 \: cm \: and \: b = 0.004 \: cm \: of \: the \: rectangle \: park}$