The area of the triangle ABC where A(0,0), B(4,0), C(0,5) IS:
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Area of the triangle ABC is 10 unit.
Step-by-step explanation:
We know area of any triangle is defined by 1 / 2 | a( d - f ) + c( e - b ) + e( b - d ) | for points ( a , b ) , ( c , d ) and ( e , f ).
Thus, here, points are A( 0, 0 ), B(4,0), C(0,5) :
= > Area of the ∆ABC = 1 / 2 | 0( 0 - 5 ) + 4( 5 - 0 ) + 0( 0 - 0 ) |
= > Area of ∆ABC = 1 / 2 | 4( 5 ) |
= > Area of ∆ABC = 1 / 2 x 4( 5 ) = 2( 5 )
= > Area of ∆ABC = 10
Thus, area of the triangle ABC is 10 unit.
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